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256=h^2
We move all terms to the left:
256-(h^2)=0
We add all the numbers together, and all the variables
-1h^2+256=0
a = -1; b = 0; c = +256;
Δ = b2-4ac
Δ = 02-4·(-1)·256
Δ = 1024
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1024}=32$$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-32}{2*-1}=\frac{-32}{-2} =+16 $$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+32}{2*-1}=\frac{32}{-2} =-16 $
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